std::find_end
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<metanoindex/>
<tbody> </tbody>| Elemento definito nell'header <algorithm>
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template< class ForwardIt1, class ForwardIt2 > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last ); |
(1) | |
template< class ForwardIt1, class ForwardIt2, class BinaryPredicate > ForwardIt1 find_end( ForwardIt1 first, ForwardIt1 last, ForwardIt2 s_first, ForwardIt2 s_last, BinaryPredicate p ); |
(2) | |
Cerca la sottosequenza ultimo
[s_first, s_last) elementi nel [first, last) gamma. La prima versione utilizza operator== di confrontare gli elementi, la seconda versione utilizza il predicato binario dato p. Original:
Searches for the last subsequence of elements
[s_first, s_last) in the range [first, last). The first version uses operator== to compare the elements, the second version uses the given binary predicate p. The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Parametri
| first, last | - | la gamma di elementi da esaminare
Original: the range of elements to examine The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| s_first, s_last | - | la gamma di elementi da cercare
Original: the range of elements to search for The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| p | - | binary predicate which returns true if the elements should be treated as equal. The signature of the predicate function should be equivalent to the following:
The signature does not need to have |
| Type requirements | ||
-ForwardIt1 must meet the requirements of ForwardIterator.
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-ForwardIt2 must meet the requirements of ForwardIterator.
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Valore di ritorno
Iterator all'inizio
[s_first, s_last) sottosuccessione ultima gamma [first, last).Original:
Iterator to the beginning of last subsequence
[s_first, s_last) in range [first, last).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Se non sottosequenza non viene trovato, viene restituito
last. (fino al c++11)Original:
If no such subsequence is found,
last is returned. (fino al c++11)The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Se
[s_first, s_last) è vuoto o se non sottosequenza non viene trovato, viene restituito last. (dal C++11)Original:
If
[s_first, s_last) is empty or if no such subsequence is found, last is returned. (dal C++11)The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Complessità
Fa a confronto la maggior parte
S*(N-S+1) dove S = distance(s_first, s_last) e N = distance(first, last).Original:
Does at most
S*(N-S+1) comparisons where S = distance(s_first, s_last) and N = distance(first, last).The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
Possibile implementazione
| First version |
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template<class ForwardIt1, class ForwardIt2>
ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last)
{
if (s_first == s_last)
return last;
ForwardIt1 result = last;
while (1) {
ForwardIt1 new_result = std::search(first, last, s_first, s_last);
if (new_result == last) {
return result;
} else {
result = new_result;
first = result;
++first;
}
}
return result;
}
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| Second version |
template<class ForwardIt1, class ForwardIt2, class BinaryPredicate>
ForwardIt1 find_end(ForwardIt1 first, ForwardIt1 last,
ForwardIt2 s_first, ForwardIt2 s_last,
BinaryPredicate p)
{
if (s_first == s_last)
return last;
ForwardIt1 result = last;
while (1) {
ForwardIt1 new_result = std::search(first, last, s_first, s_last, p);
if (new_result == last) {
return result;
} else {
result = new_result;
first = result;
++first;
}
}
return result;
}
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Esempio
Il codice seguente utilizza
find_end() per la ricerca di due diverse sequenze di numeri .
Original:
The following code uses
find_end() to search for two different sequences of numbers.
The text has been machine-translated via Google Translate.
You can help to correct and verify the translation. Click here for instructions.
You can help to correct and verify the translation. Click here for instructions.
#include <algorithm>
#include <iostream>
#include <vector>
int main()
{
std::vector<int> v{1, 2, 3, 4, 1, 2, 3, 4, 1, 2, 3, 4};
std::vector<int>::iterator result;
std::vector<int> t1{1, 2, 3};
result = std::find_end(v.begin(), v.end(), t1.begin(), t1.end());
if (result == v.end()) {
std::cout << "subsequence not found\n";
} else {
std::cout << "last subsequence is at: "
<< std::distance(v.begin(), result) << "\n";
}
std::vector<int> t2{4, 5, 6};
result = std::find_end(v.begin(), v.end(), t2.begin(), t2.end());
if (result == v.end()) {
std::cout << "subsequence not found\n";
} else {
std::cout << "last subsequence is at: "
<< std::distance(v.begin(), result) << "\n";
}
}
Output:
last subsequence is at: 8
subsequence not found
Vedi anche
trova due identici (o qualche altra relazione) elementi adiacenti l'uno all'altro Original: finds two identical (or some other relationship) items adjacent to each other The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (funzione di modello) | |
(C++11) |
trova il primo elemento che soddisfi i criteri specifici Original: finds the first element satisfying specific criteria The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (funzione di modello) |
| searches for any one of a set of elements (funzione di modello) | |
ricerche di un numero di copie consecutive di un elemento in un intervallo Original: searches for a number consecutive copies of an element in a range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (funzione di modello) | |